To calculate the area of triangle \( \triangle ABC \) using the formula \( A = \frac{1}{2} a b \sin C \), we need to plug in the values given:
- \( a = 16 \) inches
- \( b = 18 \) inches
- \( C = 43^\circ \)
First, we can calculate \( \sin C \):
\[ \sin(43^\circ) \approx 0.681998 \]
Now, we can substitute the values into the area formula:
\[ A = \frac{1}{2} \times 16 \times 18 \times \sin(43^\circ) \]
Calculating inside the formula:
\[ A = \frac{1}{2} \times 16 \times 18 \times 0.681998 \]
Calculating \( 16 \times 18 = 288 \):
\[ A = \frac{1}{2} \times 288 \times 0.681998 \] \[ A = 144 \times 0.681998 \approx 98.018 \]
Rounding to the nearest square inch:
\[ A \approx 98 \text{ inches}^2 \]
Thus, the area of triangle \( \triangle ABC \) to the nearest square inch is \( 98 \) inches².
The correct response is:
98 inches²