To determine which two objects will have the strongest attractive force between them, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. The formula is:
\[ F = k \frac{|q_1 \cdot q_2|}{r^2} \]
Where:
- \( F \) is the magnitude of the force between the charges,
- \( k \) is Coulomb's constant,
- \( q_1 \) and \( q_2 \) are the magnitudes of the two charges,
- \( r \) is the distance between the charges.
For an attractive force, we need to consider one positive and one negative charge. Let's examine the pairs:
-
Object A (+1 C) and Object C (–1 C):
\( |q_1 \cdot q_2| = |1 \cdot (-1)| = 1 \) -
Object A (+1 C) and Object B (+2 C):
\( |q_1 \cdot q_2| = |1 \cdot 2| = 2 \) (not an attractive force) -
Object B (+2 C) and Object C (–1 C):
\( |q_1 \cdot q_2| = |2 \cdot (-1)| = 2 \) -
Object B (+2 C) and Object D (–2 C):
\( |q_1 \cdot q_2| = |2 \cdot (-2)| = 4 \) -
Object C (–1 C) and Object D (–2 C):
Both are negative charges, so this is not an attractive force.
From the calculations:
- The strongest attractive force is between Object B (+2 C) and Object D (–2 C), as it yields the highest product of charge magnitudes.
So, the correct response is:
object B and object D
1 answer