(2 points)

Question

Charlie and Rashan collect miniature cars. They have the same number of cars in their collections. Charlie sold 5/8
of his collection. Rashan sold 4/10
of his collection. Who sold more of their collection? Use the drop-down menus to solve and answer the problem. Compare each fraction to the benchmark fraction 1/2
.

58

Choose
1/2
and 4/10

Choose
1/2
, so 5/8

Choose
4/10
.

Choose
sold more of his collection.

Answer 1

To determine who sold more of their collection, we need to compare the fractions \( \frac{5}{8} \) and \( \frac{4}{10} \).

1. Compare \( \frac{5}{8} \) to \( \frac{1}{2} \):

   • To find a common denominator, convert \( \frac{1}{2} \) into eighths: \[ \frac{1}{2} = \frac{4}{8} \]
   • Since \( \frac{5}{8} > \frac{4}{8} \), we conclude that \( \frac{5}{8} > \frac{1}{2} \).

2. Compare \( \frac{4}{10} \) to \( \frac{1}{2} \):

   • To find a common denominator, convert \( \frac{1}{2} \) into tenths: \[ \frac{1}{2} = \frac{5}{10} \]
   • Since \( \frac{4}{10} < \frac{5}{10} \), we conclude that \( \frac{4}{10} < \frac{1}{2} \).

Now we can summarize:

• \( \frac{5}{8} \) is more than \( \frac{1}{2} \).
• \( \frac{4}{10} \) is less than \( \frac{1}{2} \).

Therefore, since \( \frac{5}{8} > \frac{4}{10} \):

Charlie sold more of his collection.