What is the surface area of a box with a length of 40, a width of 34, and a height of 3?

Answer 1

To find the surface area of a box (rectangular prism), you can use the formula:

\[ \text{Surface Area} = 2lw + 2lh + 2wh \]

where:

• \( l \) = length
• \( w \) = width
• \( h \) = height

Given:

• \( l = 40 \)
• \( w = 34 \)
• \( h = 3 \)

Now, substituting the values into the formula:

1. Calculate \( 2lw \): \[ 2lw = 2 \times 40 \times 34 = 2 \times 1360 = 2720 \]

2. Calculate \( 2lh \): \[ 2lh = 2 \times 40 \times 3 = 2 \times 120 = 240 \]

3. Calculate \( 2wh \): \[ 2wh = 2 \times 34 \times 3 = 2 \times 102 = 204 \]

Now, add these three results together to find the total surface area:

\[ \text{Surface Area} = 2720 + 240 + 204 = 3164 \]

Thus, the surface area of the box is \( \boxed{3164} \).