To show that the expression \(-7 + [(8 \cdot m) \cdot \frac{1}{8}] + 7\) is equivalent to \(m\), we can simplify it step by step.
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Start with the original expression: \[ -7 + [(8 \cdot m) \cdot \frac{1}{8}] + 7 \]
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Simplify the expression inside the brackets: \[ (8 \cdot m) \cdot \frac{1}{8} = \frac{8m}{8} = m \]
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Substitute back into the expression: \[ -7 + m + 7 \]
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Combine like terms: \[ -7 + 7 + m = 0 + m = m \]
Thus, the original expression simplifies to \(m\).
So, \(-7 + [(8 \cdot m) \cdot \frac{1}{8}] + 7\) is indeed equivalent to \(m\).