Question

Complete the table.

f(p) = p^2 + 1
p f(p)
–2
–1
0
1

Answer 1

Let's calculate \( f(p) = p^2 + 1 \) for each value of \( p \):

1. For \( p = -2 \):
\[
f(-2) = (-2)^2 + 1 = 4 + 1 = 5
\]

2. For \( p = -1 \):
\[
f(-1) = (-1)^2 + 1 = 1 + 1 = 2
\]

3. For \( p = 0 \):
\[
f(0) = 0^2 + 1 = 0 + 1 = 1
\]

4. For \( p = 1 \):
\[
f(1) = 1^2 + 1 = 1 + 1 = 2
\]

Now, we can fill in the table:

\[
\begin{array}{|c|c|}
\hline
p & f(p) \\
\hline
-2 & 5 \\
-1 & 2 \\
0 & 1 \\
1 & 2 \\
\hline
\end{array}
\]