Nan’s suitcase is on a bench. The suitcase has a mass of 14 kilograms. Nan accidentally knocks the suitcase off the bench, and the suitcase falls at a speed of 2.7 meters per second. How much kinetic energy does the suitcase have just before it hits the floor?

Question

KE=1/2mv2

Responses

18.9 J

204.12 J

51.03 J

102.06 J

Answer 1

To calculate the kinetic energy (KE) of the suitcase just before it hits the floor, you can use the formula:

\[ KE = \frac{1}{2} m v^2 \]

where:

• \( m \) is the mass in kilograms (14 kg),
• \( v \) is the velocity in meters per second (2.7 m/s).

Now plugging in the values:

\[ KE = \frac{1}{2} \times 14 , \text{kg} \times (2.7 , \text{m/s})^2 \]

Calculating \( (2.7)^2 \):

\[ (2.7)^2 = 7.29 \]

Now substituting back into the equation:

\[ KE = \frac{1}{2} \times 14 \times 7.29 \] \[ KE = 7 \times 7.29 \] \[ KE = 51.03 , \text{J} \]

Therefore, the kinetic energy of the suitcase just before it hits the floor is 51.03 J.