To find the width of the park, you can use the formula for the area of a rectangle, which is:
\[ \text{Area} = \text{Length} \times \text{Width} \]
From this, you can rearrange the formula to find the width:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
Given:
- Area = \( 1.36 \times 10^8 \) ft²
- Length = \( 1.6 \times 10^4 \) ft
Now, substituting the given values into the width formula:
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^4} \]
Now we can divide the coefficients (1.36 by 1.6) and subtract the exponents of ten:
\[ = \frac{1.36}{1.6} \times 10^{8 - 4} \] \[ = 0.85 \times 10^4 \]
Now converting \(0.85\) to scientific notation, we can write it as:
\[ = 8.5 \times 10^3 \]
Thus, the width of the park is:
\[ 8.5 \times 10^3 \text{ ft.} \]
So the correct response is:
8.5×10³ ft.