Asked by bruh no
4x - 8y = 20
3x + 4y = 5
How can you eliminate the y-terms in this system?
multiply by ___ on both sides
3x + 4y = 5
How can you eliminate the y-terms in this system?
multiply by ___ on both sides
Answers
Answered by
GPT-4o mini
To eliminate the \( y \)-terms in the system of equations, you'll want to make the coefficients of \( y \) equal in both equations.
Here are the equations you have:
1. \( 4x - 8y = 20 \)
2. \( 3x + 4y = 5 \)
To eliminate \( y \), you can multiply the first equation by \( 1 \) (which doesn't change it) and the second equation by \( 2 \) (so the coefficients of \( y \) will be the same in magnitude).
1. \( 4x - 8y = 20 \) (multiply by \( 1 \))
2. \( 3x + 4y = 5 \) (multiply by \( 2 \))
After multiplying the second equation by \( 2 \), we get:
\[
2(3x + 4y) = 2(5)
\]
\[
6x + 8y = 10
\]
Now you have the system:
1. \( 4x - 8y = 20 \)
2. \( 6x + 8y = 10 \)
Now you can add both equations together to eliminate \( y \):
\[
(4x - 8y) + (6x + 8y) = 20 + 10
\]
\[
10x = 30
\]
So, to eliminate the \( y \)-terms, multiply the second equation by \( 2 \).
Here are the equations you have:
1. \( 4x - 8y = 20 \)
2. \( 3x + 4y = 5 \)
To eliminate \( y \), you can multiply the first equation by \( 1 \) (which doesn't change it) and the second equation by \( 2 \) (so the coefficients of \( y \) will be the same in magnitude).
1. \( 4x - 8y = 20 \) (multiply by \( 1 \))
2. \( 3x + 4y = 5 \) (multiply by \( 2 \))
After multiplying the second equation by \( 2 \), we get:
\[
2(3x + 4y) = 2(5)
\]
\[
6x + 8y = 10
\]
Now you have the system:
1. \( 4x - 8y = 20 \)
2. \( 6x + 8y = 10 \)
Now you can add both equations together to eliminate \( y \):
\[
(4x - 8y) + (6x + 8y) = 20 + 10
\]
\[
10x = 30
\]
So, to eliminate the \( y \)-terms, multiply the second equation by \( 2 \).
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