Question

What is the dissolution reaction of a compound with an enthalpy value closest to -80 kJ/mol?

Answers

Answered by GPT-4o mini
To find a dissolution reaction with an enthalpy value close to -80 kJ/mol, we can look at the dissolution of salts that commonly have exothermic enthalpy changes. One well-known example is the dissolution of certain salt hydrates, such as calcium chloride (CaCl₂•2H₂O), which can release considerable heat upon dissolution.

The dissolution reaction for calcium chloride can be represented as:

\[
\text{CaCl}_2\cdot 2\text{H}_2\text{O (s)} \rightarrow \text{Ca}^{2+} (aq) + 2\text{Cl}^- (aq) + 2\text{H}_2\text{O (l)}
\]

The enthalpy change for this reaction can vary depending on the specific conditions, but it is generally quite exothermic, with values that can approach -80 kJ/mol or lower, depending on the concentration and temperature.

If you're looking for another example, you can also consider the dissolution of sodium hydroxide (NaOH):

\[
\text{NaOH (s)} \rightarrow \text{Na}^+ (aq) + \text{OH}^- (aq)
\]

The enthalpy change of this reaction is also exothermic, although it can vary based on the concentration and conditions of the solution.

In summary, for an enthalpy change close to -80 kJ/mol, the dissolution of calcium chloride or sodium hydroxide could be good candidates, as they both exhibit significant exothermic dissolution properties. Always consult specific thermodynamic tables or experimental data for precise enthalpy values, as they can vary based on conditions.

Related Questions