Question
Determine the x-intercept(s) of the function that translates the original function f(x)=x2
𝑓
(
𝑥
)
=
𝑥
2
down 4 units.(1 point)
Responses
x=−2
𝑥
=
−
2
and x=2
𝑥
=
2
x equals negative 2 and x equals 2
x=−16
𝑥
=
−
16
and x=16
𝑥
=
16
x equals negative 3.464 and x equals 3.464
There are no x-intercepts.
There are no x -intercepts.
x=−4
𝑥
=
−
4
and x=4
𝑓
(
𝑥
)
=
𝑥
2
down 4 units.(1 point)
Responses
x=−2
𝑥
=
−
2
and x=2
𝑥
=
2
x equals negative 2 and x equals 2
x=−16
𝑥
=
−
16
and x=16
𝑥
=
16
x equals negative 3.464 and x equals 3.464
There are no x-intercepts.
There are no x -intercepts.
x=−4
𝑥
=
−
4
and x=4
Answers
Answered by
GPT-4o mini
To determine the x-intercepts of the function that translates the original function \( f(x) = x^2 \) down 4 units, we first rewrite the function after the translation.
The original function \( f(x) = x^2 \) becomes:
\[
f(x) = x^2 - 4
\]
To find the x-intercepts, we set \( f(x) \) to 0 and solve for \( x \):
\[
x^2 - 4 = 0
\]
Adding 4 to both sides gives:
\[
x^2 = 4
\]
Taking the square root of both sides, we find:
\[
x = \pm 2
\]
Thus, the x-intercepts are:
\[
x = -2 \quad \text{and} \quad x = 2
\]
So the correct answer is:
**x = -2 and x = 2**.
The original function \( f(x) = x^2 \) becomes:
\[
f(x) = x^2 - 4
\]
To find the x-intercepts, we set \( f(x) \) to 0 and solve for \( x \):
\[
x^2 - 4 = 0
\]
Adding 4 to both sides gives:
\[
x^2 = 4
\]
Taking the square root of both sides, we find:
\[
x = \pm 2
\]
Thus, the x-intercepts are:
\[
x = -2 \quad \text{and} \quad x = 2
\]
So the correct answer is:
**x = -2 and x = 2**.