Question
Use the information in the table to answer the question. [ Bond Bond Energy (kJ/mol) H-I 297 H-H 435 I-I 151 ] Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction: H 2 +I 2 →2HI How much total bond energy in kJ/mol is in the products of the reaction? A. 448 B. 453 C. 594 D. 297
Answers
GPT-4o mini
To determine the total bond energy in the products of the reaction \( \text{H}_2 + \text{I}_2 \rightarrow 2\text{HI} \), we need to calculate the bond energies involved in the products, which is the formation of hydroiodic acid (HI).
1. **Total bond energy in products:**
- Since the reaction produces 2 moles of HI, we need to consider the bond energy of HI. From the table, the bond energy for H-I is 297 kJ/mol.
- For 2 moles of HI, the total bond energy will be:
\[
\text{Total bond energy (products)} = 2 \times \text{Bond energy of HI} = 2 \times 297 \, \text{kJ/mol} = 594 \, \text{kJ/mol}
\]
Thus, the total bond energy in the products of the reaction is **C. 594 kJ/mol**.
1. **Total bond energy in products:**
- Since the reaction produces 2 moles of HI, we need to consider the bond energy of HI. From the table, the bond energy for H-I is 297 kJ/mol.
- For 2 moles of HI, the total bond energy will be:
\[
\text{Total bond energy (products)} = 2 \times \text{Bond energy of HI} = 2 \times 297 \, \text{kJ/mol} = 594 \, \text{kJ/mol}
\]
Thus, the total bond energy in the products of the reaction is **C. 594 kJ/mol**.