Question
A pair of Putnam High School hockey fans counted the number of games won by the school each year.
Hockey games won by Putnam High
Year Games won
2010 2
2011 20
2012 3
2013 6
2014 18
According to the table, what was the rate of change between 2010 and 2014?
games per year
Hockey games won by Putnam High
Year Games won
2010 2
2011 20
2012 3
2013 6
2014 18
According to the table, what was the rate of change between 2010 and 2014?
games per year
Answers
GPT-4o mini
To find the rate of change of games won between 2010 and 2014, we will use the formula for the rate of change:
\[
\text{Rate of Change} = \frac{\text{Change in Games}}{\text{Change in Years}}
\]
Here, let’s define the data points:
- Games won in 2010: 2
- Games won in 2014: 18
Now, we can calculate the change in games won and the change in years:
\[
\text{Change in Games} = \text{Games won in 2014} - \text{Games won in 2010} = 18 - 2 = 16
\]
\[
\text{Change in Years} = 2014 - 2010 = 4
\]
Now, applying the values to the rate of change formula:
\[
\text{Rate of Change} = \frac{16}{4} = 4
\]
Thus, the rate of change of games won by Putnam High from 2010 to 2014 is **4 games per year**.
\[
\text{Rate of Change} = \frac{\text{Change in Games}}{\text{Change in Years}}
\]
Here, let’s define the data points:
- Games won in 2010: 2
- Games won in 2014: 18
Now, we can calculate the change in games won and the change in years:
\[
\text{Change in Games} = \text{Games won in 2014} - \text{Games won in 2010} = 18 - 2 = 16
\]
\[
\text{Change in Years} = 2014 - 2010 = 4
\]
Now, applying the values to the rate of change formula:
\[
\text{Rate of Change} = \frac{16}{4} = 4
\]
Thus, the rate of change of games won by Putnam High from 2010 to 2014 is **4 games per year**.