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A triangle a b c is shown with angle a measuring 4 x plus 14, angle b measuring 5 x plus 4, and angle c measuring 6 x minus 3.
Use the Triangle Angle Sum Theorem to find the measure of the angles for the triangle in the diagram.
(1 point)
Responses
57°, 54°, and 69°
57 degrees , 54 degrees , and 69 degrees
54°, 44°, and 82°
54 degrees , 44 degrees , and 82 degrees
59°, 63°, and 48°
59 degrees , 63 degrees , and 48 degrees
59°, 58°, and 63°
59 degrees , 58 degrees , and 63 degrees
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A triangle a b c is shown with angle a measuring 4 x plus 14, angle b measuring 5 x plus 4, and angle c measuring 6 x minus 3.
Use the Triangle Angle Sum Theorem to find the measure of the angles for the triangle in the diagram.
(1 point)
Responses
57°, 54°, and 69°
57 degrees , 54 degrees , and 69 degrees
54°, 44°, and 82°
54 degrees , 44 degrees , and 82 degrees
59°, 63°, and 48°
59 degrees , 63 degrees , and 48 degrees
59°, 58°, and 63°
59 degrees , 58 degrees , and 63 degrees
Skip to navigation
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the measures of the angles in triangle \( ABC \) using the Triangle Angle Sum Theorem, we start by setting up the equation based on the given expressions for the angles:
\[
\text{Angle } A = 4x + 14, \quad \text{Angle } B = 5x + 4, \quad \text{Angle } C = 6x - 3
\]
According to the Triangle Angle Sum Theorem, the sum of the angles in a triangle is 180 degrees:
\[
(4x + 14) + (5x + 4) + (6x - 3) = 180
\]
Now combining like terms:
\[
4x + 5x + 6x + 14 + 4 - 3 = 180
\]
\[
15x + 15 = 180
\]
Next, we solve for \( x \):
\[
15x = 180 - 15
\]
\[
15x = 165
\]
\[
x = \frac{165}{15} = 11
\]
Now, substituting \( x = 11 \) back into the expressions for the angles:
\[
\text{Angle } A = 4(11) + 14 = 44 + 14 = 58
\]
\[
\text{Angle } B = 5(11) + 4 = 55 + 4 = 59
\]
\[
\text{Angle } C = 6(11) - 3 = 66 - 3 = 63
\]
Thus, the angles of triangle \( ABC \) are:
\[
58^\circ, 59^\circ, \text{ and } 63^\circ
\]
The correct option is:
**59°, 58°, and 63°**.
\[
\text{Angle } A = 4x + 14, \quad \text{Angle } B = 5x + 4, \quad \text{Angle } C = 6x - 3
\]
According to the Triangle Angle Sum Theorem, the sum of the angles in a triangle is 180 degrees:
\[
(4x + 14) + (5x + 4) + (6x - 3) = 180
\]
Now combining like terms:
\[
4x + 5x + 6x + 14 + 4 - 3 = 180
\]
\[
15x + 15 = 180
\]
Next, we solve for \( x \):
\[
15x = 180 - 15
\]
\[
15x = 165
\]
\[
x = \frac{165}{15} = 11
\]
Now, substituting \( x = 11 \) back into the expressions for the angles:
\[
\text{Angle } A = 4(11) + 14 = 44 + 14 = 58
\]
\[
\text{Angle } B = 5(11) + 4 = 55 + 4 = 59
\]
\[
\text{Angle } C = 6(11) - 3 = 66 - 3 = 63
\]
Thus, the angles of triangle \( ABC \) are:
\[
58^\circ, 59^\circ, \text{ and } 63^\circ
\]
The correct option is:
**59°, 58°, and 63°**.
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