To solve the compound inequality \(-16 \leq 3x - 4 < 2\), we can break it into two parts and solve each part separately. ### Step 1: Solve \(-16 \leq 3x - 4\) 1. **Add 4 to both sides**: \[ -16 + 4 \leq 3x \] \[ -12 \leq 3x \] 2. **Divide by 3**: \[ -4 \leq x \] or \[ x \geq -4 \] ### Step 2: Solve \(3x - 4 < 2\) 1. **Add 4 to both sides**: \[ 3x - 4 + 4 < 2 + 4 \] \[ 3x < 6 \] 2. **Divide by 3**: \[ x < 2 \] ### Step 3: Combine the results Now we combine the results from both parts: \[ -4 \leq x < 2 \] ### Final Answer The solution to the compound inequality is: \[ x \in [-4, 2) \]