To define the equation of a line in the form \( y = mx + b \) (which represents a linear equation), we need at least two distinct points on the line to calculate the slope \( m \) and the y-intercept \( b \). However, since you've mentioned that the graph shows a curved line going downward and provided only one point, (-3, 0), it indicates that the function you're referring to is not linear.
A downward-curving graph suggests a quadratic equation or some other non-linear function. Without additional points or more information about the shape of the curve (e.g., if it's a parabola, exponential decay, etc.), we cannot write a specific equation.
If the curve is a parabola that opens downwards and passes through the point (-3, 0), a general form of a quadratic equation can be used, such as:
\[ y = a(x + 3)^2 \]
Here, the vertex form is used (the vertex is at \( (-3, 0) \)). However, we would still need another point to determine the value of \( a \) and complete the equation.
If you can provide one more point on the curve or further details about the shape, I can assist you better in finding a specific equation.
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