Question

A graph shows a curved line going downward. Its points are (0,-3.) what is the “y = mx + b” equation?

Answer 1

To find the equation of a line in the form \( y = mx + b \) given a point and the shape of the line, we need to determine the slope (\(m\)) and the y-intercept (\(b\)).

You provided the point (0, -3). In the \( y = mx + b \) form, when \( x = 0 \), the \( y \)-value is the y-intercept (\(b\)). Thus, from the point (0, -3), we can see that:

\[
b = -3
\]

However, you mentioned that the graph has a curved line going downward. The equation \( y = mx + b \) represents a linear equation, which cannot describe a curved line. Instead, curved lines are typically represented by polynomial equations, exponential functions, or other non-linear equations.

To describe the curve accurately, we would need more information, such as additional points on the curve or the specific type of function that models it (e.g., quadratic, cubic, etc.). If you only needed to find \(b\) based on the given point, then \(b = -3\) holds true, but for a full equation, we need more details about the curvature and its behavior.