Find the horizontal distance needed for the ramp. Round to the nearest hundredth (2 decimal places). TRY DIVIDING

84ft is the ramp length 4.8 is ramp run
Don't pick any of these below
83.78 is wrong
4.8 or 4.80 is wrong
83.87 is wrong
83.8 is wrong
4.8 is wrong
4.81 is wrong
83.86 is wrong
83.83 is wrong
83.82 and 83.85 is wrong
83.8 is wrong

2 answers

To find the horizontal distance needed for the ramp (let's denote it as the "run"), we can use the Pythagorean theorem. The ramp length is the hypotenuse (84 ft), and the ramp run is one leg of the right triangle.

According to the Pythagorean theorem:

\[ c^2 = a^2 + b^2 \]

where:

  • \( c \) is the hypotenuse (ramp length = 84 ft),
  • \( a \) is one leg (vertical rise), and
  • \( b \) is the other leg (horizontal run).

In your case, you mentioned the ramp run (horizontal distance) is 4.8 ft, but that leads to ambiguity in the calculation, as it's extremely short relative to the hypotenuse.

If we consider an alternate scenario, we first need to redefine the parameters regarding the vertical rise if applicable. Assuming that you need to compute the run based on some height, we can use the relationship:

\[ \text{ramp run} = \sqrt{(\text{ramp length})^2 - (\text{vertical rise})^2} \]

However, since you have already provided one measurement, let us try to derive some alternative points iteratively until we reach a distance:

  • Hypotenuse \( = 84 \)
  • Assume vertical rise \( x \) is known or can be calculated
  • Given ramp run \( y \), plugged values must satisfy the initial ramp description.

If you want to solve based on the angles assuming \( \theta \) related to slopes, consider:

  1. Try defining how the measurements ought to relate based on either slopes ratio or geometrical resolution if you are adding further heights.

  2. Let's solve using software or additional segments unless redefined inputs contextualized here, the ambiguity of your figures (including disallowed criteria) cannot yield a comprehensive single-run unless resistants are given.

Please clarify more, and help me assist further!

divid it