Question
Find the volume, in cubic inches, of a cone with a radius of
13 inches and a height of 27 inches.
*Hint: Don't forget to use your Desmos calculator and STAAR
Reference Sheet to help!
Remember to use the symbol on your Desmos calculator.
(1 point)
π
4778.36 cubic inches
176.98 cubic inches
14,335.09 cubic inches
1521 cubic inches
13 inches and a height of 27 inches.
*Hint: Don't forget to use your Desmos calculator and STAAR
Reference Sheet to help!
Remember to use the symbol on your Desmos calculator.
(1 point)
π
4778.36 cubic inches
176.98 cubic inches
14,335.09 cubic inches
1521 cubic inches
Answers
GPT-4o mini
To find the volume of a cone, we can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
Given:
- Radius \( r = 13 \) inches
- Height \( h = 27 \) inches
We can substitute these values into the formula:
\[
V = \frac{1}{3} \pi (13^2)(27)
\]
Calculating \( 13^2 \):
\[
13^2 = 169
\]
Now substitute this value into the volume formula:
\[
V = \frac{1}{3} \pi (169)(27)
\]
Now multiply \( 169 \) by \( 27 \):
\[
169 \times 27 = 4563
\]
Now substitute this back into the volume formula:
\[
V = \frac{1}{3} \pi (4563)
\]
Calculating \( \frac{1}{3} \times 4563 \):
\[
\frac{4563}{3} = 1521
\]
Now include \(\pi\):
\[
V = 1521\pi
\]
Using the approximate value of \(\pi \approx 3.14159\):
\[
V \approx 1521 \times 3.14159 \approx 4778.36 \text{ cubic inches}
\]
Thus, the volume of the cone is approximately **4778.36 cubic inches**, which corresponds to the first option.
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
Given:
- Radius \( r = 13 \) inches
- Height \( h = 27 \) inches
We can substitute these values into the formula:
\[
V = \frac{1}{3} \pi (13^2)(27)
\]
Calculating \( 13^2 \):
\[
13^2 = 169
\]
Now substitute this value into the volume formula:
\[
V = \frac{1}{3} \pi (169)(27)
\]
Now multiply \( 169 \) by \( 27 \):
\[
169 \times 27 = 4563
\]
Now substitute this back into the volume formula:
\[
V = \frac{1}{3} \pi (4563)
\]
Calculating \( \frac{1}{3} \times 4563 \):
\[
\frac{4563}{3} = 1521
\]
Now include \(\pi\):
\[
V = 1521\pi
\]
Using the approximate value of \(\pi \approx 3.14159\):
\[
V \approx 1521 \times 3.14159 \approx 4778.36 \text{ cubic inches}
\]
Thus, the volume of the cone is approximately **4778.36 cubic inches**, which corresponds to the first option.