Factor completely.

25c2–49

1 answer

To factor the expression \( 25c^2 - 49 \), we recognize that it is a difference of squares. The general form for a difference of squares is:

\[ a^2 - b^2 = (a - b)(a + b) \]

In this case, we can identify \( a = 5c \) and \( b = 7 \), since:

\[ 25c^2 = (5c)^2 \quad \text{and} \quad 49 = 7^2 \]

Now we can rewrite the expression:

\[ 25c^2 - 49 = (5c)^2 - 7^2 \]

Using the difference of squares formula, we factor it as follows:

\[ (5c - 7)(5c + 7) \]

Thus, the completely factored form of the expression \( 25c^2 - 49 \) is:

\[ \boxed{(5c - 7)(5c + 7)} \]