Question

What is the amount of heat released when 15 grams of steam condenses into water at 100 degrees Celsius?

Answer 1

To find the amount of heat released when 15 grams of steam condenses into water at 100 degrees Celsius, we can use the heat of vaporization of water. The heat of vaporization (latent heat) for water is approximately 2260 Joules per gram.

The formula to calculate the heat released during the condensation of steam is:

\[
q = m \cdot L
\]

where:
- \( q \) is the heat released,
- \( m \) is the mass of the steam (in grams),
- \( L \) is the latent heat of vaporization (in Joules per gram).

Given:
- \( m = 15 \) grams,
- \( L = 2260 \) Joules/gram.

Now plug in the values:

\[
q = 15 \, \text{grams} \times 2260 \, \text{Joules/gram}
\]
\[
q = 33900 \, \text{Joules}
\]

Thus, the amount of heat released when 15 grams of steam condenses into water at 100 degrees Celsius is **33,900 Joules**.