Nan’s suitcase is on a bench. The suitcase has a mass of 14 kilograms. Nan accidentally knocks the suitcase off the bench, and the suitcase falls at a speed of 2.7 meters per second. How much kinetic energy does the suitcase have just before it hits the floor?

Question

KE=12mv2


(1 point)
Responses

18.9 J
18.9 J

102.06 J
102.06 J

51.03 J
51.03 J

204.12 J

Answer 1

To calculate the kinetic energy (KE) of the suitcase just before it hits the floor, we can use the formula:

\[ KE = \frac{1}{2} mv^2 \]

Where:

• \(m\) is the mass of the suitcase (14 kg)
• \(v\) is the velocity (2.7 m/s)

Now, substituting the values into the formula:

\[ KE = \frac{1}{2} \times 14 , \text{kg} \times (2.7 , \text{m/s})^2 \]

Calculating \( (2.7)^2 \):

\[ (2.7)^2 = 7.29 , \text{m}^2/\text{s}^2 \]

Now, substituting back:

\[ KE = \frac{1}{2} \times 14 \times 7.29 \] \[ KE = 7 \times 7.29 \] \[ KE = 51.03 , \text{J} \]

So the kinetic energy of the suitcase just before it hits the floor is 51.03 J.

The correct response is:

51.03 J