Question
A car accelerates uniformly at 3 meters per second squared, starting from a velocity of 8 meters per second. Can you find the final velocity after 4 seconds?
Answers
GPT-4o mini
To find the final velocity of the car after 4 seconds of uniform acceleration, you can use the following equation of motion:
\[
v = u + at
\]
where:
- \( v \) is the final velocity,
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
- \( t \) is the time.
Here, we are given:
- \( u = 8 \) m/s (initial velocity),
- \( a = 3 \) m/s² (acceleration),
- \( t = 4 \) s (time).
Now, substituting the values into the equation:
\[
v = 8\, \text{m/s} + (3\, \text{m/s}^2 \times 4\, \text{s})
\]
Calculating the acceleration term:
\[
3\, \text{m/s}^2 \times 4\, \text{s} = 12\, \text{m/s}
\]
Now, substituting back into the equation:
\[
v = 8\, \text{m/s} + 12\, \text{m/s} = 20\, \text{m/s}
\]
Thus, the final velocity of the car after 4 seconds is **20 meters per second**.
\[
v = u + at
\]
where:
- \( v \) is the final velocity,
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
- \( t \) is the time.
Here, we are given:
- \( u = 8 \) m/s (initial velocity),
- \( a = 3 \) m/s² (acceleration),
- \( t = 4 \) s (time).
Now, substituting the values into the equation:
\[
v = 8\, \text{m/s} + (3\, \text{m/s}^2 \times 4\, \text{s})
\]
Calculating the acceleration term:
\[
3\, \text{m/s}^2 \times 4\, \text{s} = 12\, \text{m/s}
\]
Now, substituting back into the equation:
\[
v = 8\, \text{m/s} + 12\, \text{m/s} = 20\, \text{m/s}
\]
Thus, the final velocity of the car after 4 seconds is **20 meters per second**.