suppose a fear cylinder and call all share the same radius and the cylinder and call also share the same height which is twice the radius which of the following is true about the relationship between the volume formulas for sphere cylinder and cold

1 answer

Let's analyze the volume formulas for a cylinder, sphere, and cone.

  1. Cylinder: The formula for the volume \( V \) of a cylinder is given by: \[ V_{\text{cylinder}} = \pi r^2 h \] Given that the height \( h \) is twice the radius \( r \) (i.e., \( h = 2r \)), we can substitute this into the formula: \[ V_{\text{cylinder}} = \pi r^2 (2r) = 2\pi r^3 \]

  2. Sphere: The formula for the volume \( V \) of a sphere is: \[ V_{\text{sphere}} = \frac{4}{3} \pi r^3 \]

  3. Cone: The formula for the volume \( V \) of a cone is: \[ V_{\text{cone}} = \frac{1}{3} \pi r^2 h \] Substituting \( h = 2r \), we get: \[ V_{\text{cone}} = \frac{1}{3} \pi r^2 (2r) = \frac{2}{3} \pi r^3 \]

Now we have the volumes:

  • Volume of the cylinder: \( V_{\text{cylinder}} = 2\pi r^3 \)
  • Volume of the sphere: \( V_{\text{sphere}} = \frac{4}{3} \pi r^3 \)
  • Volume of the cone: \( V_{\text{cone}} = \frac{2}{3} \pi r^3 \)

Relationship Between Volumes

  • The volume of the cylinder is 3 times the volume of the cone: \[ V_{\text{cylinder}} = 3 \cdot V_{\text{cone}} \quad \text{(since } 2\pi r^3 = 3 \cdot \frac{2}{3} \pi r^3\text{)} \]

  • The volume of the sphere is actually equal to \( \frac{2}{3} \) of the volume of the cylinder: \[ V_{\text{sphere}} = \frac{2}{3} V_{\text{cylinder}} \quad \text{(since } \frac{4}{3} \pi r^3 = \frac{2}{3} (2\pi r^3)\text{)} \]

Summary

  • Cylinder volume = 3 × Cone volume.
  • Sphere volume = \( \frac{2}{3} \) × Cylinder volume.

These relationships show how the volumes of these shapes relate to each other given the conditions of the problem.