To determine the electric flux through a cube with a uniformly distributed charge of +Q, we can use Gauss's law. Gauss's law states that the electric flux \(\Phi_E\) through a closed surface is equal to the charge enclosed \(Q_{\text{enc}}\) divided by the permittivity of free space \(\epsilon_0\):
\[ \Phi_E = \frac{Q_{\text{enc}}}{\epsilon_0} \]
In this case, the closed surface is the cube, and since the entire charge +Q is uniformly distributed throughout the cube, the charge enclosed by the Gaussian surface (the cube) is Q.
Thus, applying Gauss's law:
\[ \Phi_E = \frac{Q}{\epsilon_0} \]
Therefore, the net electric flux through the cube is:
\[ \frac{Q}{\epsilon_0} \]
So the correct answer is:
\(\frac{Q}{\epsilon_0}\).
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