Question
What is the kinetic energy of a 5 kg bicycle traveling at 8 m/s using the formula kinetic energy = 1/2 mv^2?
Answers
GPT-4o mini
To calculate the kinetic energy (KE) of a bicycle using the formula:
\[
KE = \frac{1}{2} mv^2
\]
where:
- \( m \) is the mass of the bicycle (5 kg),
- \( v \) is the velocity (8 m/s).
Plugging in the values:
\[
KE = \frac{1}{2} \times 5 \, \text{kg} \times (8 \, \text{m/s})^2
\]
Calculating \( (8 \, \text{m/s})^2 \):
\[
(8 \, \text{m/s})^2 = 64 \, \text{m}^2/\text{s}^2
\]
Now substituting that back into the equation:
\[
KE = \frac{1}{2} \times 5 \, \text{kg} \times 64 \, \text{m}^2/\text{s}^2
\]
Calculating the multiplication:
\[
KE = \frac{1}{2} \times 320 \, \text{kg m}^2/\text{s}^2
\]
\[
KE = 160 \, \text{J}
\]
Thus, the kinetic energy of the bicycle is **160 joules**.
\[
KE = \frac{1}{2} mv^2
\]
where:
- \( m \) is the mass of the bicycle (5 kg),
- \( v \) is the velocity (8 m/s).
Plugging in the values:
\[
KE = \frac{1}{2} \times 5 \, \text{kg} \times (8 \, \text{m/s})^2
\]
Calculating \( (8 \, \text{m/s})^2 \):
\[
(8 \, \text{m/s})^2 = 64 \, \text{m}^2/\text{s}^2
\]
Now substituting that back into the equation:
\[
KE = \frac{1}{2} \times 5 \, \text{kg} \times 64 \, \text{m}^2/\text{s}^2
\]
Calculating the multiplication:
\[
KE = \frac{1}{2} \times 320 \, \text{kg m}^2/\text{s}^2
\]
\[
KE = 160 \, \text{J}
\]
Thus, the kinetic energy of the bicycle is **160 joules**.