Alex and Ben ran in a 200-yd dash. When Alex crossed the finish line, Ben was 15 yards behind him. They then repeated the race with Alex starting 15 yards behind the starting line. Who won the repeated race and by how many yards?

1 answer

To analyze the race results between Alex and Ben, we can set up the information systematically.

  1. First Race:
    • Distance of the race: 200 yards.
    • When Alex finishes the race (200 yards), Ben is 15 yards behind. Therefore, when Alex has run 200 yards, Ben has only run \( 200 - 15 = 185 \) yards.

Let's denote:

  • \( t_A \) = time it took Alex to run 200 yards
  • \( t_B \) = time it took Ben to run 185 yards

Since both run the same time duration in the first race:

  • Alex's speed \( v_A = \frac{200}{t_A} \)
  • Ben's speed \( v_B = \frac{185}{t_B} \)

Since they ran at the same time, \[ t_A = t_B \]

This gives us the equations: \[ v_A \cdot t_A = 200 \quad \text{and} \quad v_B \cdot t_B = 185 \]

From the above, we can express \( v_B \) in terms of \( v_A \): \[ v_A = \frac{200}{t_A} \] \[ v_B = \frac{185}{t_A} \] Thus, \[ \frac{v_B}{v_A} = \frac{185}{200} = \frac{37}{40} \]

This implies that Ben runs at 37/40 of the speed of Alex.

  1. Second Race:
    • In the second race, Alex starts 15 yards behind, meaning he runs 200 + 15 = 215 yards.
    • Ben runs the usual 200 yards.

We can determine how long it takes each to finish the second race:

Let \( t_{A2} \) be the time for Alex in the second race: \[ t_{A2} = \frac{215}{v_A} \]

And Ben's time \( t_{B2} \) is: \[ t_{B2} = \frac{200}{v_B} \]

Since we established \( v_B = \frac{37}{40} v_A \), we can rewrite Ben's time: \[ t_{B2} = \frac{200}{\frac{37}{40} v_A} = \frac{200 \cdot 40}{37 v_A} = \frac{8000}{37 v_A} \]

Now we can compare both times:

  • For Alex: \[ t_{A2} = \frac{215}{v_A} \]
  • For Ben: \[ t_{B2} = \frac{8000}{37 v_A} \]

To compare: We compare \( t_{A2} \) to \( t_{B2} \). Setting up the comparison: \[ \frac{215}{v_A} \quad \text{vs} \quad \frac{8000}{37 v_A} \]

Since \( v_A \) is common in both expressions, we can ignore \( v_A \) when comparing: \[ 215 \quad \text{vs} \quad \frac{8000}{37} \]

Calculating \( \frac{8000}{37} \): \[ \frac{8000}{37} \approx 216.22 \]

Thus, \( 215 < 216.22 \) implies \( t_{A2} < t_{B2} \). This means Alex finishes before Ben in the second race.

  1. By how many yards did Alex win? To find out the number of yards Alex wins by, we calculate how far Ben runs while Alex finishes: Using the time for Alex \( t_{A2} = \frac{215}{v_A} \): \[ \text{Distance Ben covers in time } t_{A2} = v_B \cdot t_{A2} = \frac{37}{40}v_A \cdot \frac{215}{v_A} = \frac{37}{40} \cdot 215 = \frac{37 \times 215}{40} \] Calculating the distance. \[ \text{Distance Ben covered} = \frac{37 \times 215}{40} \approx 199.875 \text{ yards} \] Thus, the distance Ben fell short of the finish line: \[ 200 - 199.875 = 0.125 \text{ yards} \]

Therefore, Alex wins the second race by about 0.125 yards, or approximately 1.5 inches.