Question
A cone-shaped container on a farm is used for storing animal feed. The container has a radius of 4 feet and a height of 12 feet. (1 point)
The volume of feed, in cubic feet, this container can store is
*Hint: Don't forget to use your Desmos calculator and STAAR Reference Sheet to help!
Remember to use the symbol on your Desmos calculator.
The volume of feed, in cubic feet, this container can store is
*Hint: Don't forget to use your Desmos calculator and STAAR Reference Sheet to help!
Remember to use the symbol on your Desmos calculator.
Answers
GPT-4o mini
The volume \( V \) of a cone can be calculated using the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height of the cone.
Given:
- Radius \( r = 4 \) feet
- Height \( h = 12 \) feet
We can substitute these values into the formula:
\[
V = \frac{1}{3} \pi (4^2)(12)
\]
Calculating \( 4^2 \):
\[
4^2 = 16
\]
Now substitute that back into the volume formula:
\[
V = \frac{1}{3} \pi (16)(12)
\]
Now, multiply \( 16 \) by \( 12 \):
\[
16 \times 12 = 192
\]
So now we have:
\[
V = \frac{1}{3} \pi (192) = \frac{192}{3} \pi = 64 \pi
\]
To find the approximate numerical value, we can use \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \approx 200.96
\]
Thus, the volume of the cone-shaped container is approximately:
\[
V \approx 200.96 \text{ cubic feet}
\]
In summary, the volume of feed this container can store is \( 64\pi \) cubic feet, or approximately 200.96 cubic feet.
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height of the cone.
Given:
- Radius \( r = 4 \) feet
- Height \( h = 12 \) feet
We can substitute these values into the formula:
\[
V = \frac{1}{3} \pi (4^2)(12)
\]
Calculating \( 4^2 \):
\[
4^2 = 16
\]
Now substitute that back into the volume formula:
\[
V = \frac{1}{3} \pi (16)(12)
\]
Now, multiply \( 16 \) by \( 12 \):
\[
16 \times 12 = 192
\]
So now we have:
\[
V = \frac{1}{3} \pi (192) = \frac{192}{3} \pi = 64 \pi
\]
To find the approximate numerical value, we can use \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \approx 200.96
\]
Thus, the volume of the cone-shaped container is approximately:
\[
V \approx 200.96 \text{ cubic feet}
\]
In summary, the volume of feed this container can store is \( 64\pi \) cubic feet, or approximately 200.96 cubic feet.