Question

Complete the table.

f(m) = 2m2 + 8
m f(m)
–3
–1
1
3

Answer 1

To complete the table for the function \( f(m) = 2m^2 + 8 \), we will calculate \( f(m) \) for each value of \( m \) given.

1. For \( m = -3 \):
\[
f(-3) = 2(-3)^2 + 8 = 2(9) + 8 = 18 + 8 = 26
\]

2. For \( m = -1 \):
\[
f(-1) = 2(-1)^2 + 8 = 2(1) + 8 = 2 + 8 = 10
\]

3. For \( m = 1 \):
\[
f(1) = 2(1)^2 + 8 = 2(1) + 8 = 2 + 8 = 10
\]

4. For \( m = 3 \):
\[
f(3) = 2(3)^2 + 8 = 2(9) + 8 = 18 + 8 = 26
\]

Now we can fill in the table:

\[
\begin{array}{|c|c|}
\hline
m & f(m) \\
\hline
-3 & 26 \\
-1 & 10 \\
1 & 10 \\
3 & 26 \\
\hline
\end{array}
\]

So the completed table is:

\[
\begin{array}{|c|c|}
\hline
m & f(m) \\
\hline
-3 & 26 \\
-1 & 10 \\
1 & 10 \\
3 & 26 \\
\hline
\end{array}
\]