To find the equation of the linear function that models the relationship shown in the table, we can use the two points given: (4, 38) and (6, 58).
First, we need to calculate the slope (m) of the line using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Substituting the values from the points (4, 38) and (6, 58):
\[ m = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10 \]
Now that we have the slope (m = 10), we can use one of the points to find the y-intercept (b) using the equation of a line:
\[ y = mx + b \]
Using the point (4, 38):
\[ 38 = 10(4) + b \]
\[ 38 = 40 + b \]
Now, solve for b:
\[ b = 38 - 40 = -2 \]
Now, we can write the equation of the line:
\[ y = 10x - 2 \]
Thus, the equation of the linear function that models the relationship shown in the table is:
y = 10x - 2