Question
what is the Pythagorean triple
for the lengths 60,25,65
65 is the hypotenuse
60 is the vertical leg
25 is the horizontal leg
for the lengths 60,25,65
65 is the hypotenuse
60 is the vertical leg
25 is the horizontal leg
Answers
GPT-4o mini
To verify if the lengths 60, 25, and 65 form a Pythagorean triple, we can use the Pythagorean theorem, which states that in a right triangle:
\[ a^2 + b^2 = c^2 \]
where \( c \) is the length of the hypotenuse, and \( a \) and \( b \) are the lengths of the other two legs.
In your case:
- \( a = 25 \) (horizontal leg)
- \( b = 60 \) (vertical leg)
- \( c = 65 \) (hypotenuse)
Now we can plug the values into the Pythagorean theorem:
\[
25^2 + 60^2 = 65^2
\]
Calculating each term:
\[
25^2 = 625
\]
\[
60^2 = 3600
\]
\[
65^2 = 4225
\]
Now adding \( 25^2 \) and \( 60^2 \):
\[
625 + 3600 = 4225
\]
Since both sides of the equation are equal:
\[
4225 = 4225
\]
This confirms that \( 60, 25, \) and \( 65 \) indeed form a Pythagorean triple, with \( 65 \) as the hypotenuse.
\[ a^2 + b^2 = c^2 \]
where \( c \) is the length of the hypotenuse, and \( a \) and \( b \) are the lengths of the other two legs.
In your case:
- \( a = 25 \) (horizontal leg)
- \( b = 60 \) (vertical leg)
- \( c = 65 \) (hypotenuse)
Now we can plug the values into the Pythagorean theorem:
\[
25^2 + 60^2 = 65^2
\]
Calculating each term:
\[
25^2 = 625
\]
\[
60^2 = 3600
\]
\[
65^2 = 4225
\]
Now adding \( 25^2 \) and \( 60^2 \):
\[
625 + 3600 = 4225
\]
Since both sides of the equation are equal:
\[
4225 = 4225
\]
This confirms that \( 60, 25, \) and \( 65 \) indeed form a Pythagorean triple, with \( 65 \) as the hypotenuse.