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Part 1
The length of the base of an isosceles triangle is x. The length of a leg is 33xminus−55. The perimeter of the triangle is 9595. Find x.

1 answer

To find the value of \(x\), we start by writing the equation for the perimeter of the isosceles triangle.

The perimeter \(P\) of the triangle can be expressed as:

\[ P = \text{base} + 2 \times \text{leg} \]

In your case, the base is \(x\), and each leg is \(33x - 55\). Therefore, the perimeter can be written as:

\[ P = x + 2(33x - 55) \]

We are given that the perimeter is 9595, so we set up the following equation:

\[ x + 2(33x - 55) = 9595 \]

Now, we can simplify and solve for \(x\):

  1. Distribute the 2:

\[ x + 66x - 110 = 9595 \]

  1. Combine like terms:

\[ 67x - 110 = 9595 \]

  1. Add 110 to both sides:

\[ 67x = 9595 + 110 \] \[ 67x = 9705 \]

  1. Finally, divide by 67:

\[ x = \frac{9705}{67} \]

Calculating the division:

\[ x = 145 \]

The value of \(x\) is \(145\).