Question

Question
The average human heart beats about 3.5×107
times per year. The current population of Massachusetts is about 7×106
people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)

Answer 1

To find the total number of heartbeats in Massachusetts per year, we can multiply the average number of heartbeats per person per year by the population of Massachusetts.

Given:
- Average heartbeats per year per person = \(3.5 \times 10^7\)
- Population of Massachusetts = \(7 \times 10^6\)

Now we can perform the multiplication:

\[
\text{Total heartbeats} = (3.5 \times 10^7) \times (7 \times 10^6)
\]

To multiply these numbers, we can first multiply the coefficients (3.5 and 7) and then add the exponents (7 and 6) of 10:

\[
3.5 \times 7 = 24.5
\]
\[
10^7 \times 10^6 = 10^{7 + 6} = 10^{13}
\]

Now, combine these results:

\[
\text{Total heartbeats} = 24.5 \times 10^{13}
\]

Finally, we need to express \(24.5\) in scientific notation. Since \(24.5\) can be expressed as \(2.45 \times 10^1\), we can rewrite the total:

\[
24.5 \times 10^{13} = (2.45 \times 10^1) \times 10^{13} = 2.45 \times 10^{1 + 13} = 2.45 \times 10^{14}
\]

Therefore, the total number of heartbeats that occur in Massachusetts per year is:

\[
\boxed{2.45 \times 10^{14}}
\]