To find the volume of the cone-shaped container, we use the formula for the volume of a cone, which is:
\[ V = \frac{1}{3} \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- \( r = 4 \) feet,
- \( h = 12 \) feet.
Now, substituting the values into the formula:
\[ V = \frac{1}{3} \pi (4)^2 (12) \]
Calculating \( (4)^2 \):
\[ (4)^2 = 16 \]
Now substitute back into the equation:
\[ V = \frac{1}{3} \pi (16) (12) \]
Now calculate \( 16 \times 12 \):
\[ 16 \times 12 = 192 \]
So we have:
\[ V = \frac{1}{3} \pi (192) \]
Calculating \( \frac{192}{3} \):
\[ \frac{192}{3} = 64 \]
Thus:
\[ V = 64 \pi \]
Now, using \( \pi \approx 3.14 \):
\[ V \approx 64 \times 3.14 \approx 200.96 \]
So rounding off, we find:
\[ V \approx 201.06 \text{ cubic feet} \]
Therefore, the volume of feed this container can store is 201.06 cubic feet.