Question
A cone-shaped container on a farm is used for storing animal feed. The container has a radius of 4 feet and a height of 12 feet.
The volume of feed, in cubic feet, this container can store is _____.
603.19
16.76
201.06
The volume of feed, in cubic feet, this container can store is _____.
603.19
16.76
201.06
Answers
GPT-4o mini
To find the volume of the cone-shaped container, we use the formula for the volume of a cone, which is:
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- \( r = 4 \) feet,
- \( h = 12 \) feet.
Now, substituting the values into the formula:
\[
V = \frac{1}{3} \pi (4)^2 (12)
\]
Calculating \( (4)^2 \):
\[
(4)^2 = 16
\]
Now substitute back into the equation:
\[
V = \frac{1}{3} \pi (16) (12)
\]
Now calculate \( 16 \times 12 \):
\[
16 \times 12 = 192
\]
So we have:
\[
V = \frac{1}{3} \pi (192)
\]
Calculating \( \frac{192}{3} \):
\[
\frac{192}{3} = 64
\]
Thus:
\[
V = 64 \pi
\]
Now, using \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \approx 200.96
\]
So rounding off, we find:
\[
V \approx 201.06 \text{ cubic feet}
\]
Therefore, the volume of feed this container can store is **201.06 cubic feet**.
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- \( r = 4 \) feet,
- \( h = 12 \) feet.
Now, substituting the values into the formula:
\[
V = \frac{1}{3} \pi (4)^2 (12)
\]
Calculating \( (4)^2 \):
\[
(4)^2 = 16
\]
Now substitute back into the equation:
\[
V = \frac{1}{3} \pi (16) (12)
\]
Now calculate \( 16 \times 12 \):
\[
16 \times 12 = 192
\]
So we have:
\[
V = \frac{1}{3} \pi (192)
\]
Calculating \( \frac{192}{3} \):
\[
\frac{192}{3} = 64
\]
Thus:
\[
V = 64 \pi
\]
Now, using \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \approx 200.96
\]
So rounding off, we find:
\[
V \approx 201.06 \text{ cubic feet}
\]
Therefore, the volume of feed this container can store is **201.06 cubic feet**.