Use the following multiplication problem to show how multiplying polynomials is a closed system.
(x2−1)(−2x+5)
say it like how a 8th grader would and easy to copy and paste
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GPT-4o mini
Sure! Let's look at the multiplication problem \((x^2 - 1)(-2x + 5)\) and see how multiplying polynomials works in a closed system.
1. **Write the Expression:**
We start with \((x^2 - 1)(-2x + 5)\).
2. **Use the Distributive Property:**
We will distribute each term in the first polynomial \((x^2 - 1)\) to each term in the second polynomial \((-2x + 5)\).
- First, distribute \(x^2\) to both terms in \((-2x + 5)\):
- \(x^2 \cdot -2x = -2x^3\)
- \(x^2 \cdot 5 = 5x^2\)
- Next, distribute \(-1\) to both terms in \((-2x + 5)\):
- \(-1 \cdot -2x = 2x\)
- \(-1 \cdot 5 = -5\)
3. **Combine All the Terms:**
Now, we bring all those terms together:
\(-2x^3 + 5x^2 + 2x - 5\)
4. **Final Result:**
So, when we multiply, we get:
\(-2x^3 + 5x^2 + 2x - 5\)
### Conclusion:
This shows that when we multiply two polynomials, we still end up with another polynomial, which is why it's called a closed system. You can keep multiplying polynomials, and you won't get anything other than another polynomial!
1. **Write the Expression:**
We start with \((x^2 - 1)(-2x + 5)\).
2. **Use the Distributive Property:**
We will distribute each term in the first polynomial \((x^2 - 1)\) to each term in the second polynomial \((-2x + 5)\).
- First, distribute \(x^2\) to both terms in \((-2x + 5)\):
- \(x^2 \cdot -2x = -2x^3\)
- \(x^2 \cdot 5 = 5x^2\)
- Next, distribute \(-1\) to both terms in \((-2x + 5)\):
- \(-1 \cdot -2x = 2x\)
- \(-1 \cdot 5 = -5\)
3. **Combine All the Terms:**
Now, we bring all those terms together:
\(-2x^3 + 5x^2 + 2x - 5\)
4. **Final Result:**
So, when we multiply, we get:
\(-2x^3 + 5x^2 + 2x - 5\)
### Conclusion:
This shows that when we multiply two polynomials, we still end up with another polynomial, which is why it's called a closed system. You can keep multiplying polynomials, and you won't get anything other than another polynomial!
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