To find two numbers that multiply to 24 (the value on top) and add to 11 (the value on the bottom), we can set up the equations:
Let the two numbers be \( x \) and \( y \).
- \( x \cdot y = 24 \)
- \( x + y = 11 \)
We can solve for \( y \) in the second equation: \( y = 11 - x \)
Now, we can substitute \( y \) into the first equation:
\( x(11 - x) = 24 \)
Expanding this gives:
\( 11x - x^2 = 24 \)
Rearranging it leads to a quadratic equation:
\( x^2 - 11x + 24 = 0 \)
Now, we can factor the quadratic:
\( (x - 3)(x - 8) = 0 \)
So, the solutions for \( x \) are:
\( x = 3 \) or \( x = 8 \)
Thus, the two numbers are 3 and 8, since:
- \( 3 \cdot 8 = 24 \)
- \( 3 + 8 = 11 \)