k to the power of 3 - 6 k ^ 2 - 3K + 40 in standard form

Answer 1

To express the polynomial \( k^3 - 6k^2 - 3k + 40 \) in standard form, we simply need to arrange it in descending order of the powers of \( k \).

The given polynomial is already arranged in standard form:

\[ k^3 - 6k^2 - 3k + 40 \]

In standard form, the terms are ordered by the degree of \( k \), starting with the highest degree:

• The term with \( k^3 \) is \( k^3 \).
• The term with \( k^2 \) is \(-6k^2\).
• The term with \( k \) is \(-3k\).
• The constant term is \( +40 \).

Thus, the polynomial in standard form is:

\[ k^3 - 6k^2 - 3k + 40 \]

This representation is already in standard form, and there are no further adjustments needed.