Question

TEST Unit 3B
Aaron Medina
#7.
The table below shows the linear relationship between the distance in feet below sea level and the time in seconds traveled by a submarine.
Time (seconds)

0

Distance Below Sea Leve (feet)

380

15

545

27

677

44

864

72

1172
Time (seconds)
Distance Below Sea Level (feet)
1172
What is the rate of change (slope) of the distance in feet below sea level with respect to time that the submarine traveled? Place your answer in the box:



Rate of Change:
Math Input:

Answer 1

To find the rate of change (slope) of the distance below sea level with respect to time, we can use the formula for slope, which is:

\[
\text{slope} = \frac{\text{change in distance}}{\text{change in time}}
\]

We can select two points from the table to calculate the slope. Let's use the points (0, 380) and (72, 1172).

1. Calculate the change in distance:
- Distance at time 0 seconds: 380 feet
- Distance at time 72 seconds: 1172 feet
- Change in distance: \(1172 - 380 = 792\) feet

2. Calculate the change in time:
- Time at the first point: 0 seconds
- Time at the second point: 72 seconds
- Change in time: \(72 - 0 = 72\) seconds

3. Now, use the formula for slope:
\[
\text{slope} = \frac{792 \text{ feet}}{72 \text{ seconds}} = 11 \text{ feet per second}
\]

Thus, the rate of change (slope) of the distance below sea level with respect to time is:

\[
\text{Rate of Change: } 11
\]

Math Input: \(11\) feet per second