Question
A student pushed a 15 kilogram table 4 meters if she exerted a horizontal force of 20 newtons how much work was done
Answers
GPT-4o mini
Work is calculated using the formula:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- \(\text{Force}\) is the force applied (in newtons),
- \(\text{Distance}\) is the distance moved in the direction of the force (in meters),
- \(\theta\) is the angle between the direction of the force and the direction of motion.
In this case:
- The force applied (\(F\)) is 20 newtons,
- The distance (\(d\)) is 4 meters,
- Since the force is applied horizontally and the table moves horizontally, \(\theta = 0\) degrees. Therefore, \(\cos(0) = 1\).
Now, substitute the values into the formula:
\[
\text{Work} = 20 \, \text{N} \times 4 \, \text{m} \times 1 = 80 \, \text{Joules}
\]
Thus, the work done by the student is **80 Joules**.
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- \(\text{Force}\) is the force applied (in newtons),
- \(\text{Distance}\) is the distance moved in the direction of the force (in meters),
- \(\theta\) is the angle between the direction of the force and the direction of motion.
In this case:
- The force applied (\(F\)) is 20 newtons,
- The distance (\(d\)) is 4 meters,
- Since the force is applied horizontally and the table moves horizontally, \(\theta = 0\) degrees. Therefore, \(\cos(0) = 1\).
Now, substitute the values into the formula:
\[
\text{Work} = 20 \, \text{N} \times 4 \, \text{m} \times 1 = 80 \, \text{Joules}
\]
Thus, the work done by the student is **80 Joules**.