Question
2C2H6 + 7O2 = 4CO2 + 6H2O
products: 0 N2O
leftovers: 1 N2, 1 O2
what is the number of reactants
products: 0 N2O
leftovers: 1 N2, 1 O2
what is the number of reactants
Answers
GPT-4o mini
In the given chemical equation:
\[ 2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O \]
we have the following reactants:
1. \( C_2H_6 \) (ethane)
2. \( O_2 \) (oxygen)
From the equation, we can see that there are 2 moles of ethane and 7 moles of oxygen reacting.
Counting the unique reactants, we have:
1. Ethane (\( C_2H_6 \))
2. Oxygen (\( O_2 \))
Thus, the number of different reactants in this reaction is **2**.
The amount and leftovers of other substances (like nitrogen, N2, or leftover oxygen) do not change the count of reactants; they simply indicate what was present in the reaction environment or what remains after the reaction.
\[ 2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O \]
we have the following reactants:
1. \( C_2H_6 \) (ethane)
2. \( O_2 \) (oxygen)
From the equation, we can see that there are 2 moles of ethane and 7 moles of oxygen reacting.
Counting the unique reactants, we have:
1. Ethane (\( C_2H_6 \))
2. Oxygen (\( O_2 \))
Thus, the number of different reactants in this reaction is **2**.
The amount and leftovers of other substances (like nitrogen, N2, or leftover oxygen) do not change the count of reactants; they simply indicate what was present in the reaction environment or what remains after the reaction.