The decomposition reaction of silver bromide (AgBr) can be written as:
\[ 2 \text{AgBr} \rightarrow 2 \text{Ag} + \text{Br}_2 \]
From this balanced equation, we can see that for every 2 moles of silver bromide that decompose, 2 moles of silver and 1 mole of bromine are produced. This gives us a ratio of silver to bromine of:
\[ 2 \text{Ag} : 1 \text{Br}_2 \]
Therefore, the ratio of silver to bromine in the products of the reaction is 2:1.