According to the Law of Conservation of Mass, the mass of the reactants must equal the mass of the products. In this case, you have carbon (C) and dioxygen (O2) as reactants, and carbon dioxide (CO2) as the product.
Given:
- Mass of carbon (C) = 24 g
- Mass of carbon dioxide (CO2) produced = 98 g
To find the mass of dioxygen (O2) that reacted, we can use the equation:
\[ \text{Mass of reactants} = \text{Mass of products} \]
Substituting in the known values:
\[ \text{Mass of C} + \text{Mass of O2} = \text{Mass of CO2} \]
\[ 24, \text{g} + \text{Mass of O2} = 98, \text{g} \]
Now, we can solve for the mass of O2:
\[ \text{Mass of O2} = 98, \text{g} - 24, \text{g} = 74, \text{g} \]
Therefore, the mass of dioxygen (O2) in the reactants is 74 g.