How many atoms of carbon (C) are present in the reactants of the following chemical equation?

2C6
H10
+ 17O2
→ 12CO2
+ 10H2
O

(1 point)
Responses

1 atom
1 atom

16 atoms
16 atoms

12 atoms
12 atoms

7 atoms

1 answer

To find the number of carbon (C) atoms in the reactants of the given chemical equation:

The reactants are:

  • \(2 \text{C}6\text{H}{10}\)
  • \(17 \text{O}_2\)

Each \( \text{C}6\text{H}{10} \) molecule contains 6 carbon atoms.

So for \(2 \text{C}6\text{H}{10}\): \[ 2 \times 6 = 12 \text{ carbon atoms} \]

Thus, in the reactants, there are 12 atoms of carbon (C).

So the correct response is:

12 atoms

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