To find the total bond energy in the products of the reaction \( H_2 + Cl_2 \rightarrow 2 HCl \), we need to consider the bonds formed in the products. The reaction produces 2 moles of \( HCl \), and since each \( HCl \) molecule contains one H–Cl bond, we can calculate the bond energy for the products.
The bond energy of the H–Cl bond is given as 427 kJ/mol. Since 2 moles of \( HCl \) are produced:
\[ \text{Total bond energy in products} = 2 \times 427 , \text{kJ/mol} = 854 , \text{kJ/mol} \]
Thus, the total bond energy in the products of the reaction is 854 kJ/mol.