To find the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we need to consider the bond energies of the products, which consists of 2 moles of \( HI \).
From the table:
- The bond energy of \( H-I \) is 297 kJ/mol.
Since there are 2 moles of \( HI \) produced, the total bond energy in the products is calculated as follows:
\[ \text{Total Bond Energy} = 2 \times \text{Bond Energy of } H-I = 2 \times 297 \text{ kJ/mol} = 594 \text{ kJ/mol}. \]
Therefore, the total bond energy in the products of the reaction is:
594 kJ/mol.