Use the information in the table to answer the question.

Bond Bond Energy ( kJ/mol
)
H-I
297

H-H
435

I-I
151

Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.

H2+I2→2HI


How much total bond energy in kJ/mol
is in the products of the reaction?

(1 point)
Responses

453
453

297
297

448
448

594
594

1 answer

To find the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we need to consider the bond energies of the products, which consists of 2 moles of \( HI \).

From the table:

  • The bond energy of \( H-I \) is 297 kJ/mol.

Since there are 2 moles of \( HI \) produced, the total bond energy in the products is calculated as follows:

\[ \text{Total Bond Energy} = 2 \times \text{Bond Energy of } H-I = 2 \times 297 \text{ kJ/mol} = 594 \text{ kJ/mol}. \]

Therefore, the total bond energy in the products of the reaction is:

594 kJ/mol.