Question
Find the surface area of this cylinder.
Use the `\pi` button in your calculations and round to the nearest whole number.
Height is 40in
radius is 25in
Answer choices; 6,283
1210
16283
10210
Use the `\pi` button in your calculations and round to the nearest whole number.
Height is 40in
radius is 25in
Answer choices; 6,283
1210
16283
10210
Answers
GPT-4o mini
To find the surface area of a cylinder, you can use the formula:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
where:
- \( r \) is the radius,
- \( h \) is the height.
Given:
- Radius (\( r \)) = 25 inches
- Height (\( h \)) = 40 inches
Now, we can plug in the values:
1. Calculate the area of the two circular bases:
\[
2\pi r^2 = 2\pi (25^2) = 2\pi (625) = 1250\pi
\]
2. Calculate the area of the side (the lateral surface area):
\[
2\pi rh = 2\pi (25)(40) = 2000\pi
\]
3. Add these two areas together:
\[
\text{Total Surface Area} = 1250\pi + 2000\pi = 3250\pi
\]
Now, we round this to the nearest whole number after calculating \( 3250\pi \):
Using \( \pi \approx 3.14 \):
\[
3250 \cdot 3.14 \approx 10295
\]
Now, rounding to the nearest whole number gives \( 10295 \).
Among the answer choices provided, the closest is **10210**.
Thus, the final answer is:
**10210**.
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
where:
- \( r \) is the radius,
- \( h \) is the height.
Given:
- Radius (\( r \)) = 25 inches
- Height (\( h \)) = 40 inches
Now, we can plug in the values:
1. Calculate the area of the two circular bases:
\[
2\pi r^2 = 2\pi (25^2) = 2\pi (625) = 1250\pi
\]
2. Calculate the area of the side (the lateral surface area):
\[
2\pi rh = 2\pi (25)(40) = 2000\pi
\]
3. Add these two areas together:
\[
\text{Total Surface Area} = 1250\pi + 2000\pi = 3250\pi
\]
Now, we round this to the nearest whole number after calculating \( 3250\pi \):
Using \( \pi \approx 3.14 \):
\[
3250 \cdot 3.14 \approx 10295
\]
Now, rounding to the nearest whole number gives \( 10295 \).
Among the answer choices provided, the closest is **10210**.
Thus, the final answer is:
**10210**.