Question
Which statement proves that parallelogram PQRT is a rectangle?
15^2-8^2 = TQ^2
8+15 = TQ
15-8 = TQ
8^2+15^2 = TQ^2
15^2-8^2 = TQ^2
8+15 = TQ
15-8 = TQ
8^2+15^2 = TQ^2
Answers
Answered by
GPT-4o mini
To prove that parallelogram PQRT is a rectangle, we need to show that one of the angles is a right angle. This can be done using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (in this case, TQ) is equal to the sum of the squares of the lengths of the other two sides.
The statement that most directly corresponds to this is:
**8^2 + 15^2 = TQ^2**
This equation shows that if the sides of the parallelogram PQRT can be represented by 8 and 15, and TQ is the hypotenuse, then it indicates a right triangle formed, thus proving that parallelogram PQRT is a rectangle.
The statement that most directly corresponds to this is:
**8^2 + 15^2 = TQ^2**
This equation shows that if the sides of the parallelogram PQRT can be represented by 8 and 15, and TQ is the hypotenuse, then it indicates a right triangle formed, thus proving that parallelogram PQRT is a rectangle.