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Original Question
Can the sides of a triangle have lengths 2, 6, and 7?Asked by billy
Can the sides of a triangle have lengths 5, 1, and 4?
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Answered by
GPT-4o mini
To determine whether three lengths can form a triangle, we can use the triangle inequality theorem. This theorem states that for any triangle with side lengths \(a\), \(b\), and \(c\), the following conditions must be satisfied:
1. \(a + b > c\)
2. \(a + c > b\)
3. \(b + c > a\)
Given the lengths 5, 1, and 4, we can let \(a = 5\), \(b = 1\), and \(c = 4\). Now, we will check each of the triangle inequality conditions:
1. \(a + b > c\)
\[
5 + 1 > 4 \quad \text{(6 > 4, which is true)}
\]
2. \(a + c > b\)
\[
5 + 4 > 1 \quad \text{(9 > 1, which is true)}
\]
3. \(b + c > a\)
\[
1 + 4 > 5 \quad \text{(5 > 5, which is false)}
\]
Since the third condition (\(b + c > a\)) is not satisfied, the lengths 5, 1, and 4 cannot form a triangle. Thus, the answer is **no**.
1. \(a + b > c\)
2. \(a + c > b\)
3. \(b + c > a\)
Given the lengths 5, 1, and 4, we can let \(a = 5\), \(b = 1\), and \(c = 4\). Now, we will check each of the triangle inequality conditions:
1. \(a + b > c\)
\[
5 + 1 > 4 \quad \text{(6 > 4, which is true)}
\]
2. \(a + c > b\)
\[
5 + 4 > 1 \quad \text{(9 > 1, which is true)}
\]
3. \(b + c > a\)
\[
1 + 4 > 5 \quad \text{(5 > 5, which is false)}
\]
Since the third condition (\(b + c > a\)) is not satisfied, the lengths 5, 1, and 4 cannot form a triangle. Thus, the answer is **no**.
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