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Can the sides of a triangle have lengths 2, 6, and 7?Asked by billy
Can the sides of a triangle have lengths 2, 16, and 17?
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Answered by
GPT-4o mini
To determine if the lengths 2, 16, and 17 can form a triangle, we must use the triangle inequality theorem. The theorem states that for any triangle with sides of lengths \(a\), \(b\), and \(c\), the following conditions must be satisfied:
1. \(a + b > c\)
2. \(a + c > b\)
3. \(b + c > a\)
Let's denote the sides as follows:
- \(a = 2\)
- \(b = 16\)
- \(c = 17\)
Now, we will check each of the triangle inequalities:
1. \(a + b > c\):
\[
2 + 16 > 17 \quad \text{(which simplifies to)} \quad 18 > 17 \quad \text{(True)}
\]
2. \(a + c > b\):
\[
2 + 17 > 16 \quad \text{(which simplifies to)} \quad 19 > 16 \quad \text{(True)}
\]
3. \(b + c > a\):
\[
16 + 17 > 2 \quad \text{(which simplifies to)} \quad 33 > 2 \quad \text{(True)}
\]
Since all three conditions of the triangle inequality are satisfied, the lengths 2, 16, and 17 can indeed form a triangle.
1. \(a + b > c\)
2. \(a + c > b\)
3. \(b + c > a\)
Let's denote the sides as follows:
- \(a = 2\)
- \(b = 16\)
- \(c = 17\)
Now, we will check each of the triangle inequalities:
1. \(a + b > c\):
\[
2 + 16 > 17 \quad \text{(which simplifies to)} \quad 18 > 17 \quad \text{(True)}
\]
2. \(a + c > b\):
\[
2 + 17 > 16 \quad \text{(which simplifies to)} \quad 19 > 16 \quad \text{(True)}
\]
3. \(b + c > a\):
\[
16 + 17 > 2 \quad \text{(which simplifies to)} \quad 33 > 2 \quad \text{(True)}
\]
Since all three conditions of the triangle inequality are satisfied, the lengths 2, 16, and 17 can indeed form a triangle.
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