To determine which point is a solution for the given simultaneous inequalities \(y \leq 4x - 5\) and \(y < 2x - 7\), we need to check each point against both inequalities.
-
(7, 12):
- For \(y \leq 4x - 5\):
- \(12 \leq 4(7) - 5 \Rightarrow 12 \leq 28 - 5 \Rightarrow 12 \leq 23\) (True)
- For \(y < 2x - 7\):
- \(12 < 2(7) - 7 \Rightarrow 12 < 14 - 7 \Rightarrow 12 < 7\) (False)
- For \(y \leq 4x - 5\):
-
(5, 3):
- For \(y \leq 4x - 5\):
- \(3 \leq 4(5) - 5 \Rightarrow 3 \leq 20 - 5 \Rightarrow 3 \leq 15\) (True)
- For \(y < 2x - 7\):
- \(3 < 2(5) - 7 \Rightarrow 3 < 10 - 7 \Rightarrow 3 < 3\) (False)
- For \(y \leq 4x - 5\):
-
(0, 15):
- For \(y \leq 4x - 5\):
- \(15 \leq 4(0) - 5 \Rightarrow 15 \leq 0 - 5 \Rightarrow 15 \leq -5\) (False)
- For \(y \leq 4x - 5\):
-
(15, 0):
- For \(y \leq 4x - 5\):
- \(0 \leq 4(15) - 5 \Rightarrow 0 \leq 60 - 5 \Rightarrow 0 \leq 55\) (True)
- For \(y < 2x - 7\):
- \(0 < 2(15) - 7 \Rightarrow 0 < 30 - 7 \Rightarrow 0 < 23\) (True)
- For \(y \leq 4x - 5\):
Based on the evaluations, the point (15, 0) satisfies both inequalities.
So the correct answer is:
(15, 0)